Two circles have centers that are d units apart, and each has diameter d. For any d, let A(d) be the area of the smallest circle that contains both of these circles. Find limd→∞d2A(d).
Solution
Solution:
This equals limd→∞d2π(2d+d)2=4π.
Want a route through all this instead of an archive? The track
puts 2,000 problems in a working order, from AMC 10 level to the IMO shortlist.
Source: MathNet,
licensed CC-BY-4.0.
Statement reproduced verbatim; metadata (topic, difficulty) added by this project.