Maths Olympiad Prep

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, 2013

Number theory Difficulty 4.5 AIME Find the answer United States

Problem:

How many positive integers less than 100100 are relatively prime to 200200? (Two numbers are relatively prime if their greatest common factor is 11.)

A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.

Solution

Solution:

A positive integer n<100n < 100 is relatively prime to 200200 if and only if it is relatively prime to 100100 (since 200200 and 100100 have the same prime factors). Thus, our answer is φ(100)=100×12×45=40\varphi(100) = 100 \times \frac{1}{2} \times \frac{4}{5} = 40.

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Source: MathNet, licensed CC-BY-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project.