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Croatia Mathematical Competitions

Geometry Difficulty 5.5 AIME, harder Prove it Croatia

Let ABCDABCD be a tetrahedron such that ∠BAC=∠CAD=∠DAB=90∘\angle BAC = \angle CAD = \angle DAB = 90^\circ, ∣AD∣=22|AD| = 2\sqrt{2} and ∣AB∣=∣AC∣=3|AB| = |AC| = 3 holds. Determine the radius of the inscribed sphere of the tetrahedron. (Mea Bombardelli)

Solution

MATHEMATICAL COMPETITIONS IN CROATIA IN 2015
If a1a_1 and z1z_1 are connected by bus, let us put A′={z1,g,a1,…,an}A' = \{z_1, g, a_1, \dots, a_n\} and Z′={z2,…,zm}Z' = \{z_2, \dots, z_m\}. Then (A′,Z′)(A', Z') is a good pair and the number of elements of A′∪Z′A' \cup Z' is greater than the number of elements of A∪ZA \cup Z, which contradicts the assumption.
If a1a_1 and z1z_1 are connected by train, let us put A′′={a2,…,an}A'' = \{a_2, \dots, a_n\} and Z′′={a1,g,z1,z2,…,zm}Z'' = \{a_1, g, z_1, z_2, \dots, z_m\}. Then (A′′,Z′′)(A'', Z'') is a good pair and the number of elements of A′′∪Z′′A'' \cup Z'' is greater than the number of elements of A∪ZA \cup Z, which contradicts the assumption.
Since all cases lead to contradiction, we conclude that the assumption was wrong and that every city is either in the set AA or in the set ZZ.
3.4. Let F′F' be the intersection of the circumcircle of the triangle ABDABD and the line BGBG (different from BB).

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