Maths Olympiad Prep

Library / /8 of 27

Geometry Difficulty 5.5 AIME, harder Prove it Croatia

Let ABCDABCD be a tetrahedron such that BAC=CAD=DAB=90\angle BAC = \angle CAD = \angle DAB = 90^\circ, AD=22|AD| = 2\sqrt{2} and AB=AC=3|AB| = |AC| = 3 holds. Determine the radius of the inscribed sphere of the tetrahedron. (Mea Bombardelli)

Solution

MATHEMATICAL COMPETITIONS IN CROATIA IN 2015
If a1a_1 and z1z_1 are connected by bus, let us put A={z1,g,a1,,an}A' = \{z_1, g, a_1, \dots, a_n\} and Z={z2,,zm}Z' = \{z_2, \dots, z_m\}. Then (A,Z)(A', Z') is a good pair and the number of elements of AZA' \cup Z' is greater than the number of elements of AZA \cup Z, which contradicts the assumption.
If a1a_1 and z1z_1 are connected by train, let us put A={a2,,an}A'' = \{a_2, \dots, a_n\} and Z={a1,g,z1,z2,,zm}Z'' = \{a_1, g, z_1, z_2, \dots, z_m\}. Then (A,Z)(A'', Z'') is a good pair and the number of elements of AZA'' \cup Z'' is greater than the number of elements of AZA \cup Z, which contradicts the assumption.
Since all cases lead to contradiction, we conclude that the assumption was wrong and that every city is either in the set AA or in the set ZZ.
3.4. Let FF' be the intersection of the circumcircle of the triangle ABDABD and the line BGBG (different from BB).

Want a route through all this instead of an archive? The track puts 2,000 problems in a working order, from AMC 10 level to the IMO shortlist.

Source: MathNet, licensed CC-BY-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project.