Let k be a positive integer no less than 3 and θ be a real number. Prove that, if both cos(k−1)θ and coskθ are rational numbers, then there exists a positive integer n>k, such that both cos(n−1)θ and cosnθ are rational numbers.
Solution
First we prove a lemma. Lemma Let α be a real number. If cosα is rational, then cosmα is rational for any positive integer m. We prove by induction on m. By cos2α=2cos2α−1, we get that the lemma is true for m=2. We suppose that the lemma is true for m≤l (l≥2). Since cos(l+1)α=2coslα⋅cosα−cos(l−1)α, then we conclude that the lemma is true for m=l+1 and our induction is complete. By the lemma, setting m=k, m=k+1 for α=kθ, (k−1)θ, it follows that cosk2θ, cos(k2−1)θ are rational numbers. Since k2>k, the statement holds.
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