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Algebra Difficulty 4.1 AIME Find the answer Italy

How much is 220+227+231+232+237+2404\sqrt[4]{2^{20}+2^{27}+2^{31}+2^{32}+2^{37}+2^{40}} ?

A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.

Solution

The answer is 1056. Once a factor 2202^{20} has been collected under the fourth root, one is led to compute 1+27+211+212+217+2204\sqrt[4]{1+2^{7}+2^{11}+2^{12}+2^{17}+2^{20}}. At this point it is possible to recognize in the expression under the root the square of the trinomial 1+26+210=(25+1)21+2^{6}+2^{10}=(2^{5}+1)^{2} or to directly verify that it is the fourth power of 25+12^{5}+1. The expression as a whole is therefore equal to 25(25+1)2^{5}(2^{5}+1), that is 1056.

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Source: MathNet, licensed CC-BY-4.0. Statement translated into English from the original; metadata (topic, difficulty) added by this project.