Maths Olympiad Prep

Library / /53 of 94

Geometry Difficulty 4.8 AIME Prove it United States

Problem:

Let CC be a circle with two diameters intersecting at an angle of 3030 degrees. A circle SS is tangent to both diameters and to CC, and has radius 11. Find the largest possible radius of CC.

Solution

Solution:

For CC to be as large as possible we want SS to be as small as possible. It is not hard to see that this happens in the situation shown below. Then the radius of CC is 1+csc15=1+2+61 + \csc 15 = \mathbf{1} + \sqrt{\mathbf{2}} + \sqrt{\mathbf{6}}. The computation of sin15\sin 15 can be done via the half angle formula.

Figure 1

Want a route through all this instead of an archive? The track puts 2,000 problems in a working order, from AMC 10 level to the IMO shortlist.

Source: MathNet, licensed CC-BY-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project.