Maths Olympiad Prep

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Algebra Difficulty 4.7 AIME Prove it Soviet Union

Problem:
Show that x4+y4+z2xyz8x^4 + y^4 + z^2 \geq xyz\sqrt{8} for all positive reals xx, yy, zz.

Solution

Solution:
By AM/GM, x4+y42x2y2x^4 + y^4 \geq 2x^2y^2. Then by AM/GM again, 2x2y2+z2(8)xyz2x^2y^2 + z^2 \geq (\sqrt{8})xyz.

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Source: MathNet, licensed CC-BY-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project.