1. Given that O is a point inside △ABC, and satisfies OA⋅OB=OB⋅OC=OC⋅OA.
Then point O is the △ABC's .
A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.
Solution
ニ、1. Orthocenter. From OA⋅OB=OB⋅OC we can get OB⋅AC=0, so, point O lies on the altitude of side AC. Similarly, we can prove that point O also lies on the altitudes of the other sides. Therefore, point O is the orthocenter of △ABC.
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