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Geometry Difficulty 4.8 AIME Find the answer

1. Given that OO is a point inside ABC\triangle A B C, and satisfies
OAOB=OBOC=OCOA O A \cdot O B=O B \cdot O C=O C \cdot O A \text {. }

Then point OO is the ABC\triangle A B C's \qquad .

A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.

Solution

ニ、1. Orthocenter.
From OAOB=OBOCO A \cdot O B=O B \cdot O C we can get OBAC=0O B \cdot A C=0, so, point OO lies on the altitude of side ACA C. Similarly, we can prove that point OO also lies on the altitudes of the other sides. Therefore, point OO is the orthocenter of ABC\triangle A B C.

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Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic and difficulty added by this site.