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Algebra Difficulty 2.1 Junior Find the answer

The fraction a4b4a2b2\frac{a^{-4}-b^{-4}}{a^{-2}-b^{-2}} is equal to:
(A) a6b6\textbf{(A)}\ a^{-6}-b^{-6}(B) a2b2\textbf{(B)}\ a^{-2}-b^{-2}(C) a2+b2(D) a2+b2\textbf{(C)}\ a^{-2}+b^{-2}\\ \textbf{(D)}\ a^2+b^2(E) a2b2\textbf{(E)}\ a^2-b^2

Multiple choice: answer with the letter of the option you want.

Solution

By the difference of squares property, a4b4a^{-4} - b^{-4} is equivalent to (a2+b2)(a2b2)(a^{-2} + b^{-2})(a^{-2} - b^{-2}). This means the fraction is now equal to (a2+b2)(a2b2)a2b2\frac{(a^{-2} + b^{-2})(a^{-2} - b^{-2})}{a^{-2} - b^{-2}}, which simplifies to (C) a2+b2\textbf{(C)}\ a^{-2}+b^{-2}

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Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic and difficulty added by this site.