8. (HUN 1) For a given positive integer k denote the square of the sum of its digits by f1(k) and let fn+1(k)=f1(fn(k)). Determine the value of f1991(21990).
A number or a short expression. Spacing and $ signs are ignored.
Solution
8. Since 21990>0. Thus f3(21990)=r2 where r>1. Hence f1991(21990)=256.
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