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Algebra Difficulty 2.2 Junior Find the answer

For how many values of the coefficient a do the equations x2+ax+1=0x2xa=0\begin{align*}x^2+ax+1=0 \\ x^2-x-a=0\end{align*} have a common real solution?

Pick one

Solution

Subtracting the equations, we get ax+x+1+a=0ax+x+1+a=0, or (x+1)(a+1)=0(x+1)(a+1)=0, so x=1x=-1 or a=1a=-1. If x=1x=-1, then a=2a=2, which satisfies the condition. If a=1a=-1, then xx is nonreal. This means that a=1a=-1 is the only number that works, so our answer is (B)(B).
~alexanderruan

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Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic and difficulty added by this site.