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Algebra Difficulty 2.8 Junior Find the answer

Given two lines l1:x+2y1=0l_1: x + 2y - 1 = 0 and l2:mxy=0l_2: mx - y = 0 are perpendicular, then m=m =

Pick one

Solution

Since line l1:x+2y1=0l_1: x + 2y - 1 = 0 and line l2:mxy=0l_2: mx - y = 0 are perpendicular to each other,
we can obtain m2=0m - 2 = 0. Solving this equation yields m=2m = 2.
Therefore, the correct choice is: A\boxed{\text{A}}.
By establishing an equation about mm based on the condition that the two lines are perpendicular to each other, solving it will yield the value of the real number mm.
This problem provides an equation of a line containing the letter parameter mm, and asks for the value of mm under the condition that they are perpendicular to each other. It focuses on the necessary and sufficient condition for two lines to be perpendicular, making it a basic question.

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Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic and difficulty added by this site.