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Algebra Difficulty 2.0 Junior Find the answer

32+54+98+1716+3332+6564−7=\frac{3}{2}+\frac{5}{4}+\frac{9}{8}+\frac{17}{16}+\frac{33}{32}+\frac{65}{64}-7=

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Solution

Solution by e_power_pi_times_i
Simplifying, we have 9664+8064+7264+6864+6664+6564−7\frac{96}{64}+\frac{80}{64}+\frac{72}{64}+\frac{68}{64}+\frac{66}{64}+\frac{65}{64}-7, which is 96+80+72+68+66+6564−7=44764−7=66364−7=(A) −164\frac{96+80+72+68+66+65}{64}-7 = \frac{447}{64}-7 = 6\frac{63}{64}-7 = \boxed{\textbf{(A) } -\frac{1}{64}}.

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Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic and difficulty added by this site.