Maths Olympiad Prep

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Number theory Difficulty 5.4 AIME, harder Find the answer

26. Find the least positive residue of
a) 3103^{10} modulo 11
b) 2122^{12} modulo 13
c) 5165^{16} modulo 17
d) 3223^{22} modulo 23 .
e) Can you propose a theorem from the above congruences?

A number or a short expression. Spacing and $ signs are ignored.

Solutions — 2

Solution 1

26. a) 1 b) 1 c) 1 d) 1 e) ap11(modp)a^{p-1} \equiv 1(\bmod p) when pp is prime and pap \nmid a

Solution 2

26. a) 1 b) 1 c) 1 d) 1 e) ap11(modp)a^{p-1} \equiv 1 \pmod{p} when pp is prime and pap \nmid a

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Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic and difficulty added by this site.