Maths Olympiad Prep

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Algebra Difficulty 5.1 AIME, harder Find the answer

5. The function defined on the domain RR
f(x)=lgx21 f(x)=|\lg | x-2||-1 \text{. }

If b<0b<0, then the equation concerning xx
f2(x)+bf(x)=0 f^{2}(x)+b f(x)=0

has \qquad distinct real roots.

A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.

Solution

5. 8 .

From the problem, we know that the graph of y=lgxy=\lg x is first symmetrical about the yy-axis, then the part below the xx-axis is flipped up, followed by a rightward shift of 2 units and a downward shift of 1 unit to form the graph of f(x)f(x). The zeros of g(x)=f2(x)+bf(x)g(x)=f^{2}(x)+b f(x) are the roots of the equation. It is easy to see that g(x)g(x) has 8 zeros.

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Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic and difficulty added by this site.