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Algebra Difficulty 4.7 AIME Find the answer

2. If 1=xyx+y,2=yzy+z,3=zx2+x1=\frac{x y}{x+y}, 2=\frac{y z}{y+z}, 3=\frac{z x}{2+x}, then the value of xx is

A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.

Solution

(Given: from the equations 1x+1y=1,1y+\frac{1}{x}+\frac{1}{y}=1, \frac{1}{y}+ 1z\frac{1}{z} =121z+1x=13x=125.=\frac{1}{2} \cdot \frac{1}{z}+\frac{1}{x}=\frac{1}{3} \cdot x=\frac{12}{5}.)

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Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic and difficulty added by this site.