Maths Olympiad Prep

Library / /89 of 520

Number theory Difficulty 5.6 AIME, harder Find the answer

11. Find a good choice for the multiplier aa in the pure multiplicative pseudo-random number generator xnaxn1(mod2251)x_{n} \equiv a x_{n-1}\left(\bmod 2^{25}-1\right). (Hint: Find a primitive root of 22512^{25}-1 and then take an appropriate power of this root.)

A number or a short expression. Spacing and $ signs are ignored.

Solution

None

Want a route through all this instead of an archive? The track puts 2,000 problems in a working order, from AMC 10 level to the IMO shortlist.

Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic and difficulty added by this site.