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Algebra Difficulty 1.9 Junior Find the answer

Let xx be a real number such that secxtanx=2\sec x - \tan x = 2. Then secx+tanx=\sec x + \tan x =

Pick one

Solution

(secxtanx)(secx+tanx)=sec2xtan2x=1(\sec x - \tan x)(\sec x + \tan x) = \sec^{2} x - \tan^{2} x = 1, so secx+tanx=(E) 0.5\sec x + \tan x = \boxed{\textbf{(E)}\ 0.5}.

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Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic and difficulty added by this site.