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Combinatorics Difficulty 2.8 Junior Find the answer

In a class of 54 students, the selection situation for the elective topics "Selected Lectures on Geometric Proofs" and "Polar Coordinates and Parametric Equations" is as follows (each student selects at least one topic): 6 students selected both topics, and the number of students who selected "Polar Coordinates and Parametric Equations" is 8 more than those who selected "Selected Lectures on Geometric Proofs". How many students selected only "Selected Lectures on Geometric Proofs"?

A number or a short expression. Spacing and $ signs are ignored.

Solution

Let AA be the set of students who selected the topic "Selected Lectures on Geometric Proofs", and let BB be the set of students who selected the topic "Polar Coordinates and Parametric Equations".

Then, ABA \cup B represents the entire class.

Let the cardinality of AA be xx, then the cardinality of BB is x+8x + 8.

The cardinality of ABA \cup B is 54, and the cardinality of ABA \cap B is 6.

Since the cardinality of ABA \cup B equals the sum of the cardinalities of AA and BB minus the cardinality of ABA \cap B, we have:

54=x+(x+8)654 = x + (x + 8) - 6

Solving for xx, we get x=26x = 26.

Therefore, the number of students who selected only "Selected Lectures on Geometric Proofs" is 266=2026 - 6 = 20 students.

Hence, the answer is 20\boxed{20}.

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Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic and difficulty added by this site.