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Algebra Difficulty 3.2 AMC 10/12 Find the answer

In an "online test," the number of correct answers for a certain group are 1010, 88, 66, 99, 88, 77, 88. For this set of data, which of the following judgments is incorrect?

Pick one

Solution

To analyze the given data and determine which judgment is incorrect, we proceed step by step as follows:

1. Calculate the Mean:
Mean=10+8+6+9+8+7+87=567=8 Mean = \frac{10 + 8 + 6 + 9 + 8 + 7 + 8}{7} = \frac{56}{7} = 8
Therefore, judgment C, stating that the mean is 88, is correct.

2. Determine the Median:
First, arrange the data in ascending order: 6,7,8,8,8,9,106, 7, 8, 8, 8, 9, 10.
The median is the middle number, which is 88.
Therefore, judgment B, stating that the median is 88, is correct.

3. Identify the Mode:
The number 88 appears 33 times, which is more frequent than any other number in the set.
Therefore, judgment A, stating that the mode is 88, is correct.

4. Calculate the Variance:
The variance formula for this sample is:
S2=1ni=1n(xixˉ)2 S^2 = \frac{1}{n}\sum_{i=1}^{n}(x_i - \bar{x})^2
Substituting the mean xˉ=8\bar{x} = 8 and the given values, we get:
S2=17[(108)2+(88)2+(68)2+(98)2+(88)2+(78)2+(88)2] S^2 = \frac{1}{7}[(10-8)^2 + (8-8)^2 + (6-8)^2 + (9-8)^2 + (8-8)^2 + (7-8)^2 + (8-8)^2]
Simplifying the above expression:
S2=17[4+0+4+1+0+1+0]=107=1.42857... S^2 = \frac{1}{7}[4 + 0 + 4 + 1 + 0 + 1 + 0] = \frac{10}{7} = 1.42857...
This shows that the variance is not 88, but approximately 1.431.43.

Therefore, the judgment that is incorrect is option D, which states that the variance is 88. Hence, the answer is D\boxed{D}.

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Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic and difficulty added by this site.