Competition problem — Combinatorics

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Combinatorics Difficulty 5.2 AIME, harder Find the answer

4. Find all subsets of the integers $2,3,4,7,11,13,16$ that have 18 as their sum.

Your answer

A number or a short expression. Spacing and $ signs are ignored.

Solution

4. $18=2+16=2+3+13=3+4+11=7+11$

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Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic and difficulty added by this site.