17. y=x2+x+1x2−x+n ( n is a positive integer) has a minimum value of an, a maximum value of bn, and cn=4n(1+3anbn). Prove: 23−n+11<k=1∑nck1<2−n1(n⩾2)
Solution
17. First prove anbn=34n−1,cn=n2.
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