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Algebra Difficulty 1.9 Junior Find the answer

let n=xyxyn=x-y^{x-y}. Find nn when x=2x=2 and y=2y=-2:

Pick one

Solution

Substitute the variables to determine the value of nn.
n=2(2)2(2)n = 2 - (-2)^{2-(-2)}
n=2(2)4n = 2 - (-2)^4
n=216n = 2 - 16
n=14n = -14
The answer is (A)\boxed{\textbf{(A)}}.

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Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic and difficulty added by this site.