Competition problem — Algebra — Maths Olympiad Prep

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Algebra Difficulty 2.1 Junior Find the answer

Given the universal set $U=\mathbb{R}$ , set $A=\{x|-2\leq x\leq 3\}$ , and set $B=\{x|x<-1\}$ , then the set $A\cap B$ equals to ____.

Your answer

A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.

Solution

Since $A=\{x|-2\leq x\leq 3\}$ and $B=\{x|x<-1\}$ ,
we have $A\cap B=\{x|-2\leq x<-1\}$ .
Therefore, the answer is $\boxed{\{x|-2\leq x<-1\}}$ .

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