Maths Olympiad Prep

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Combinatorics Difficulty 2.9 Junior Find the answer

The addition below is incorrect. What is the largest digit that can be changed to make the addition correct?
 6 4 18 5 2+9 7 32 4 5 6\begin{array}{rr}&\ \texttt{6 4 1}\\ &\texttt{8 5 2}\\ &+\texttt{9 7 3}\\ \hline &\texttt{2 4 5 6}\end{array}

Pick one

Solution

Doing the addition as is, we get 641+852+973=2466641 + 852 + 973 = 2466. This number is 1010 larger than the desired sum of 24562456. Therefore, we must make one of the three numbers 1010 smaller.
We may either change 641631641 \rightarrow 631, 852842852 \rightarrow 842, or 973963973 \rightarrow 963. Either change results in a valid sum. The largest digit that could be changed is thus the 77 in the number 973973, and the answer is (D) 7\boxed{\textbf{(D) }7}.

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Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic and difficulty added by this site.