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Geometry Difficulty 2.3 Junior Find the answer

Joy has 3030 thin rods, one each of every integer length from 1 cm1 \text{ cm} through 30 cm30 \text{ cm}. She places the rods with lengths 3 cm3 \text{ cm}, 7 cm7 \text{ cm}, and 15cm15 \text{cm} on a table. She then wants to choose a fourth rod that she can put with these three to form a quadrilateral with positive area. How many of the remaining rods can she choose as the fourth rod?

Pick one

Solution

The quadrilateral cannot be a straight line. Thus, the fourth side must be longer than 15(3+7)=515 - (3 + 7) = 5 and shorter than 15+3+7=2515 + 3 + 7 = 25. This means Joy can use the 1919 possible integer rod lengths that fall into [6,24][6, 24]. However, she has already used the rods of length 77 cm and 1515 cm so the answer is 192=1719 - 2 = 17 (B)\boxed{\textbf{(B)}}

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Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic and difficulty added by this site.