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Geometry Difficulty 1.9 Junior Find the answer

The point OO is the center of the circle circumscribed about triangle ABCABC, with BOC=120\angle BOC = 120^{\circ} and AOB=140\angle AOB = 140^{\circ}, as shown. What is the degree measure of ABC\angle ABC?
2007 12B AMC-3.png

Pick one

Solution

Since triangles ABOABO and BOCBOC are isosceles, ABO=20o\angle ABO=20^o and OBC=30o\angle OBC=30^o. Therefore, ABC=50o\angle ABC=50^o, or (D)\mathrm{(D)}.

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