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Algebra Difficulty 2.4 Junior Find the answer

The solution of the equation 7x+7=8x7^{x+7} = 8^x can be expressed in the form x=logb77x = \log_b 7^7. What is bb?

Pick one

Solution

This problem is quickly solved with knowledge of the laws of exponents and logarithms.
\begin{align*} 7^{x+7} &= 8^x \\ 7^x*7^7 &= 8^x \\ \left(\frac{8}{7}\right)^x &= 7^7 \\ x &= \log_{8/7}7^7 \end{align*}
Since we are looking for the base of the logarithm, our answer is (C) 87\boxed{\textbf{(C)}\ \frac{8}{7}}.

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Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic and difficulty added by this site.