Maths Olympiad Prep

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Combinatorics Difficulty 4.7 AIME Find the answer

1. (7 points) In the equality 124816=191-2-4-8-16=19, place several modulus signs so that it becomes correct.

A number or a short expression. Spacing and $ signs are ignored.

Solution

Answer. || 124816=191-2|-| 4-8|-16|=19.

There are other examples.

Comment. It is sufficient to provide one example. It is not necessary to explain how it was obtained.

## Evaluation criteria.

## - Any correct example -7 points.

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Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic and difficulty added by this site.