Let ABC be an equilateral triangle, and BCKM be a parallelogram. Find the angle between the lines AB and KM.
#
A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.
Solution
Since VSKM is a parallelogram, line KM is parallel to line BC. Therefore, the angle between lines AB and KM is equal to the angle between lines AB and BC, i.e., 60∘.
## Answer
60∘.
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