Maths Olympiad Prep

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Number theory Difficulty 3.2 AMC 10/12 Find the answer

Among the following real numbers, the irrational number is:

Pick one

Solution

To determine which of the given numbers is irrational, we analyze each option step by step:

**Option A: 3.14159263.1415926

This number is a finite decimal, meaning it can be expressed as a fraction of two integers. Thus, it is a rational number.

Option B: 0.202002000-0.202002000

Similar to option A, this number is also a finite decimal. Therefore, it can be expressed as a fraction, making it a rational number.

Option C: 25\sqrt{25}**

The square root of 25 is equal to 5, which is an integer. Integers are a subset of rational numbers since they can be expressed as a fraction (for example, 5=515 = \frac{5}{1}). Thus, this option represents a rational number.

**Option D: 93\sqrt[3]{9}**

The cube root of 9 cannot be expressed as a fraction of two integers, making it an irrational number. Unlike the square root of a perfect square or integers, the cube root of a non-perfect cube does not simplify to a rational number.

Therefore, the correct answer, identifying the irrational number among the options, is:

D\boxed{D}

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Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic and difficulty added by this site.