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Combinatorics Difficulty 1.9 Junior Find the answer

Let function f:{1,2,3}{1,2,3}f: \{1, 2, 3\} \rightarrow \{1, 2, 3\}, then the number of functions f(x)f(x) that satisfy "if x1x2x_1 \neq x_2, then f(x1)f(x2)f(x_1) \neq f(x_2)" is

Pick one

Solution

The functions f(x)f(x) that satisfy "if x1x2x_1 \neq x_2, then f(x1)f(x2)f(x_1) \neq f(x_2)" are bijections.
The total number of such functions is A33=3×2×1=6A_3^3 = 3 \times 2 \times 1 = 6,
Therefore, the correct answer is D\boxed{D}.

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Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic and difficulty added by this site.