20. The inequality to be proved is
sin2nx+(2n−2)sinnxcosnx+cos2nx⩽1
Taking the n-th power on both sides of the identity sin2x+cos2x=1, we get
1=(sin2nx+cos2nx)+n(sin2xcosn−2x+cos2xsinn−2x)+Cn2(sin4xcosn−4x+cos4xsinn−4x)+⋯⩾(sin2nx+cos2nx)+(2n−2)sinnxcosnx
This is because the value in each parenthesis is no less than 2sinnxcosnx, and the sum of the coefficients equals 21(2n−