Maths Olympiad Prep

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Geometry Difficulty 2.9 Junior Find the answer

The three sides of a right triangle have integral lengths which form an arithmetic progression. One of the sides could have length

Pick one

Solution

Let the three sides be ad,a-d, a,a, and a+d.a+d. Because of the Pythagorean Theorem,
(ad)2+a2=(a+d)2(a-d)^2 + a^2 = (a+d)^2
This can be simplified to
a(a4d)=0.a(a-4d) = 0.
So, aa is a multiple of 4d4d and the triangle has sides 3d,4d,5d.3d, 4d, 5d. We check the answer choices for anything divisible by 3, 4, or 5. The only one that works is 81, which is divisible by 3.
The answer is (C) 81.\textbf{(C)}\ 81.
-edited by coolmath34

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Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic and difficulty added by this site.