Maths Olympiad Prep

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Algebra Difficulty 3.6 AMC 10/12 Find the answer

Teacher Zhang briefly recorded the scores of Xiao Ming and other 4 students in a group as: +10, -5, 0, +8, -3. It is also known that Xiao Ming actually scored 90 points and ranked third among these 5 students. Can you tell how much each of these 5 students scored? Please write it down and calculate the average score of these 5 students.

A number or a short expression. Spacing and $ signs are ignored.

Solution

The brief records of the scores from highest to lowest are: +10, +8, 0, -3, -5. Since Xiao Ming ranked third and scored 90 points, the brief records are based on Xiao Ming's score as the standard. First, we calculate the scores of each student, and then we calculate the average score of these 5 students.

This question examines the application of rational numbers in real life. Determining Xiao Ming's score based on his score and ranking third is key.

Let's calculate the scores of each student:
- The student with +10 scored 90+10=10090 + 10 = 100 points.
- The student with +8 scored 90+8=9890 + 8 = 98 points.
- Xiao Ming scored 9090 points.
- The student with -3 scored 903=8790 - 3 = 87 points.
- The student with -5 scored 905=8590 - 5 = 85 points.

To calculate the average score of these 5 students:
Average=100+98+90+87+855=4605=92 \text{Average} = \frac{100 + 98 + 90 + 87 + 85}{5} = \frac{460}{5} = 92

Therefore, the average score of these 5 students is 92\boxed{92}.

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Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic and difficulty added by this site.