Maths Olympiad Prep

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Geometry Difficulty 5.5 AIME, harder Prove it

Example 1 As shown in Figure 1, in ABCD\square A B C D, O\odot O passes through points A,B,CA, B, C, and EE is a point on BCB C. Let the circumcircle of ABE\triangle A B E be P\odot P, PFBCP F \perp B C, and PFP F intersects ABA B at point FF. CFC F intersects O\odot O at point GG. Prove: G,E,C,DG, E, C, D are concyclic.

Solution

【Analysis and Proof】As shown in Figure 1, extend EFEF to intersect P\odot P at point HH, and connect HGHG, HAHA.
Since PFBCPF \perp BC, by symmetry we know
AHBEAH \parallel BE
H,A,D\Rightarrow H, A, D are collinear EH=BA=CD\Rightarrow EH=BA=CD
\Rightarrow Quadrilateral HECDHECD is an isosceles trapezoid
H,E,C,D\Rightarrow H, E, C, D are concyclic.
By the intersecting chords theorem, we have
FHFE=FAFB=FGFC. FH \cdot FE = FA \cdot FB = FG \cdot FC \text{.}

Therefore, H,G,E,CH, G, E, C are concyclic.
Thus, H,G,E,C,DH, G, E, C, D are concyclic.
Hence, G,E,C,DG, E, C, D are concyclic.

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Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic and difficulty added by this site.