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Geometry Difficulty 2.8 Junior Find the answer

Let SS be the sum of the interior angles of a polygon PP for which each interior angle is 7127\frac{1}{2} times the
exterior angle at the same vertex. Then
$\textbf{

Pick one

Solution

Let ana_n be the interior angle of the nth vertex, and let bnb_n be the exterior angle of the nth vertex. From the conditions in the problem,
an=7.5bna_n = 7.5b_n
That means
a1+a2an=7.5(b1+b2bn)a_1 + a_2 \cdots a_n = 7.5(b_1 + b_2 \cdots b_n)
Since the sum of the exterior angles of a polygon is 360360^{\circ}, the equation can be simplified as
a1+a2an=7.5360a_1 + a_2 \cdots a_n = 7.5 \cdot 360
a1+a2an=2700a_1 + a_2 \cdots a_n = 2700
The sum of the interior angles is 27002700 degrees. However, there is no other constraint on what angle the interior angles can be, so we can not for sure claim that the polygon is regular or not. Thus, the answer is (E)\boxed{\textbf{(E)}}.

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Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic and difficulty added by this site.