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Algebra Difficulty 5.8 AIME, harder Prove it
3. In △ABC, prove:
(1) When n is an integer, we have
cot2nA+cot2nB+cot2nC⩾1;
(2) When n is an odd number, we have
tan22nA+tan22nB+tan22nC⩾1
Solution
3. (1) Left side ⩾cotnAcotnB+cotnBcotnC+cotnCcotnA =1.
(2) Left side ⩾tan2nAtan2nB+tan2nBtan2nC+tan2nCtan2nA=1.
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