Maths Olympiad Prep

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Geometry Difficulty 5.3 AIME, harder Prove it

7. As shown in the upper right figure, ABAB is the diameter of semicircle OO. Chords ACAC and BDBD are drawn through AA and BB, respectively. Let ACAC and BDBD intersect at EE. Tangents to the circle are drawn through CC and DD, intersecting at point PP. Connect PEPE. Prove: PEABPE \perp AB.

Solution

( Hint: Connect ADA D )、BCBC intersect at FF, then EE is the orthocenter of FAB\triangle F A B, so FEABF E \perp A B, it is sufficient to prove that PP is on EFE F, one way to prove that the tangent through (D(\therefore D's tangent lines all intersect FEF E at the midpoint. )

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