Maths Olympiad Prep

Library / /98 of 520

Algebra Difficulty 2.8 Junior Find the answer

Given that the domain of y=f(log2x)y=f(\log_{2}x) is [12,4]\left[\frac{1}{2}, 4\right], then the domain of y=f(x)y=f(x) is

Pick one

Solution

Since the domain of y=f(log2x)y=f(\log_{2}x) is [12,4]\left[\frac{1}{2}, 4\right],
it follows that 12x4\frac{1}{2} \leq x \leq 4.
Then 1log2x2-1 \leq \log_{2}x \leq 2.
Thus, the domain of y=f(x)y=f(x) is [1,2][-1, 2].
Therefore, the correct choice is: C\boxed{\text{C}}.
From the domain of y=f(log2x)y=f(\log_{2}x) being [12,4]\left[\frac{1}{2}, 4\right], we can deduce that 12x4\frac{1}{2} \leq x \leq 4, and further determine the domain of y=f(x)y=f(x).
This question examines the domain of a function and its determination method, and is a basic question.

Want a route through all this instead of an archive? The track puts 2,000 problems in a working order, from AMC 10 level to the IMO shortlist.

Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic and difficulty added by this site.