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Algebra Difficulty 6.3 National olympiad Prove it

For example, if a,b,cRa, b, c \in \mathbf{R}, then
a4+b4+c4+a3b+b3c+c3a2(ab3+bc3+ca3)a^{4}+b^{4}+c^{4}+a^{3} b+b^{3} c+c^{3} a \geqslant 2\left(a b^{3}+b c^{3}+c a^{3}\right)

Solution

Proof: Let
f(a,b,c)=a4+b4+c4+ab3+bc3+ca32(a3b+b3c+c3a)f(a, b, c)=a^{4}+b^{4}+c^{4}+a b^{3}+b c^{3}+c a^{3}-2\left(a^{3} b+b^{3} c+c^{3} a\right)

Then
f(a+t,b+t,c+t)=6(a2ab)t2+3(a3+cr a2b2cycab2)t+a4+b4+c4+ab3+bc3+ca32(a3b+b3c+c3a)\begin{array}{l} f(a+t, b+t, c+t)=6\left(\sum a^{2}-\sum a b\right) t^{2}+3\left(\sum a^{3}+\sum_{\text {cr }} a^{2} b-2 \sum_{c y c} a b^{2}\right) t+ \\ a^{4}+b^{4}+c^{4}+a b^{3}+b c^{3}+c a^{3}-2\left(a^{3} b+b^{3} c+c^{3} a\right) \end{array}

Thus, it suffices to prove
Δ(a,b,c)=3(a3+qca2b2qcab2)246(a2ab)(a4+b4+c4+ab3+bc3+ca32(a3b+b3c+c3a))0\begin{array}{l} \Delta(a, b, c)=3\left(\sum a^{3}+\sum_{q c} a^{2} b-2 \sum_{q c} a b^{2}\right)^{2}-4 \cdot 6\left(\sum a^{2}-\sum a b\right) \cdot \\ \left(a^{4}+b^{4}+c^{4}+a b^{3}+b c^{3}+c a^{3}-2\left(a^{3} b+b^{3} c+c^{3} a\right)\right) \leqslant 0 \end{array}

Notice that Δ(a,b,c)=Δ(a+t,b+t,c+t),tR\Delta(a, b, c)=\Delta(a+t, b+t, c+t), t \in \mathbf{R}, so it suffices to prove
Δ(ac,bc,0)0(3(ac)2(bc)6(ac)(bc)2+3(ac)3+3(bc)3)24(3(ac)(bc)+3(ac)2+3(bc)2)((ac)4+(bc)4+(ac)3(bc)2(ac)(bc)3)03((bc)33(ac)2(bc)+(ac)3)20\begin{array}{l} \Delta(a-c, b-c, 0) \leqslant 0 \Leftrightarrow \\ \left(3(a-c)^{2}(b-c)-6(a-c)(b-c)^{2}+3(a-c)^{3}+3(b-c)^{3}\right)^{2}- \\ 4\left(-3(a-c)(b-c)+3(a-c)^{2}+3(b-c)^{2}\right)\left((a-c)^{4}+(b-c)^{4}+\right. \\ \left.(a-c)^{3}(b-c)-2(a-c)(b-c)^{3}\right) \leqslant 0 \Leftrightarrow \\ -3\left((b-c)^{3}-3(a-c)^{2}(b-c)+(a-c)^{3}\right)^{2} \leqslant 0 \end{array}

The proposition is proved.

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Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic and difficulty added by this site.