Maths Olympiad Prep

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Geometry Difficulty 4.6 AIME Find the answer

5. In trapezoid ABCDABCD, ABCD,AB=3CD,EAB \parallel CD, AB=3CD, E is the midpoint of diagonal ACAC, and line BEBE intersects ADAD at FF. Then the value of AF:FDAF: FD is:

Pick one

Solution

5. C.

Draw CG//BFC G / / B F intersecting the extension of ADA D at GG (as shown in the figure). From ABA B //CD,CG//BF/ / C D, C G / / B F, we get ABF\triangle A B F \backsim DCG\triangle D C G, thus AF:DG=ABA F: D G=A BDC=3:1D C=3: 1. Also, by CG//BFC G / / B F, FD=εDCF D=\varepsilon D C, hence AF:Fl=32=32A F: F l=-32=\frac{3}{2}.

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