Maths Olympiad Prep

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Geometry Difficulty 5.7 AIME, harder Find the answer

Example 1. PP is a point inside an equilateral ABC\triangle A B C, and the ratio of the sizes of APB,BPC,CPA\angle A P B, \angle B P C, \angle C P A is 5:6:75: 6: 7. Then the ratio of the sizes of the three interior angles of the triangle with sides PA,PB,PCP A, P B, P C is ( ) (from smallest to largest).

Pick one

Solution

From the given, we know that APB=100,BPC=\angle A P B=100^{\circ}, \angle B P C= 120,CPA=140120^{\circ}, \angle C P A=140^{\circ}.

From the proof of the previous problem, we know that the three interior angles of the triangle with sides of lengths PA,PB,PCP A, P B, P C are (note the comparison and observation of the angles at one point):
10060,12060,14060,100^{\circ}-60^{\circ}, 120^{\circ}-60^{\circ}, 140^{\circ}-60^{\circ},

which are 40,60,8040^{\circ}, 60^{\circ}, 80^{\circ}, respectively. Therefore, their ratio is 2:3:42: 3: 4, so the answer is A.

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Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic and difficulty added by this site.