132. The line passing through the midpoints of the diagonals AC and BD of quadrilateral ABCD intersects sides AB and DC at points M and N. Prove that SDCM=SANB.
Solution
132. Let K be the midpoint of DB, and L be the midpoint of AC. SANM=SCNM (since ∣AL∣=∣LC∣), similarly SBNM=SDMN, from which the statement of the problem follows.
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