We are given:
$$\frac{b^2}{ac} = x^y$$
Taking the logarithm on both sides:
$$\log{\left(\frac{b^2}{ac}\right)} = \log{x^y}$$
Using the properties of logarithms:
$$2\log{b} - \log{a} - \log{c} = y \log{x}$$
Substituting the values given in the problem statement:
$$2q \log{x} - p \log{x} - r \log{x} = y \log{x}$$
Since $x \neq 1$, dividing each side by $\log{x}$ we get:
$$y = \boxed{\textbf{(C) } 2q - p - r}$$
~ proloto