Using the radius $r$ the three volumes can be computed as follows:
$A = \frac 13 (\pi r^2) \cdot 2r$
$M = (\pi r^2) \cdot 2r$
$C = \frac 43 \pi r^3$
Clearly, $M = A+C \Longrightarrow$ the correct answer is $\mathrm{(A)}$.
The other linear combinations are obviously non-zero, and the left hand side of $\mathrm{(D)}$ evaluates to $(\pi r^3)^2 \cdot \left( \frac 49 - 4 + \frac {16}9 \right)$ which is negative. Thus $\mathrm{(A)}$ is indeed the only correct answer.