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Algebra Difficulty 2.7 Junior Find the answer

If for any xRx \in \mathbb{R}, the inequality xax|x| \geq ax always holds, then the range of the real number aa is

Pick one

Solution

When x>0x > 0, xaxx \geq ax always holds, which means a1a \leq 1.

When x=0x = 0, 0a×00 \geq a \times 0 always holds, which means aRa \in \mathbb{R}.

When x<0x < 0, xax-x \geq ax always holds, which means a1a \geq -1.

If for any xRx \in \mathbb{R}, the inequality xax|x| \geq ax always holds, then 1a1-1 \leq a \leq 1.

Therefore, the correct choice is B\boxed{\text{B}}.

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Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic and difficulty added by this site.