Maths Olympiad Prep

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Number theory Difficulty 5.7 AIME, harder Prove it

1. Show that 399,5145,73433|99,5| 145,7 \mid 343, and 8880888 \mid 0.

Solution

1. 99=333,145=529,343=749,0=888099=3 \cdot 33,145=5 \cdot 29,343=7 \cdot 49,0=888 \cdot 0

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Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic and difficulty added by this site.