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Algebra Difficulty 2.8 Junior Find the answer

When using the completing the square method to solve the equation x2+2x1=0x^{2}+2x-1=0, the correct result is:

Pick one

Solution

To solve the equation x2+2x1=0x^{2}+2x-1=0 using the completing the square method, we follow these steps:

1. Start with the given equation:
x2+2x1=0x^{2}+2x-1=0

2. Move the constant term to the other side:
x2+2x=1x^{2}+2x = 1

3. To complete the square, we need to add (22)2=1(\frac{2}{2})^{2} = 1 to both sides of the equation. This is because the coefficient of xx is 22, and we use the formula (coefficient of x2)2\left(\frac{\text{coefficient of } x}{2}\right)^{2}:
x2+2x+1=1+1x^{2}+2x+1 = 1+1

4. Simplify the right side and write the left side as a square:
x2+2x+1=2x^{2}+2x+1 = 2
(x+1)2=2\left(x+1\right)^{2} = 2

Therefore, the equation in the form of completing the square is (x+1)2=2\boxed{(x+1)^{2}=2}, which corresponds to choice B\boxed{B}.

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Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic and difficulty added by this site.