Maths Olympiad Prep

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Combinatorics Difficulty 6.5 National olympiad Find the answer

How many distinct arrangements are possible for wearing five different rings in the five fingers of the right hand? (We can wear multiple rings in one finger)
[list=1]
[*] 10!5!\frac{10!}{5!}

[*] 555^5

[*] 9!4!\frac{9!}{4!}
[*] None of these

[/list]

Multiple choice: answer with the letter of the option you want.

Solution

To determine the number of distinct arrangements for wearing five different rings on the five fingers of the right hand, we need to consider the following:

1. Understanding the problem:
- We have 5 different rings.
- We have 5 fingers.
- Each ring can be placed on any of the 5 fingers.
- Multiple rings can be worn on the same finger.

2. Applying the multiplication principle:
- For each ring, there are 5 choices (one for each finger).
- Since the placement of each ring is independent of the others, we multiply the number of choices for each ring.

3. Calculating the total number of arrangements:
- For the first ring, there are 5 choices.
- For the second ring, there are 5 choices.
- For the third ring, there are 5 choices.
- For the fourth ring, there are 5 choices.
- For the fifth ring, there are 5 choices.

Therefore, the total number of distinct arrangements is:
5×5×5×5×5=55 5 \times 5 \times 5 \times 5 \times 5 = 5^5

4. Verification:
- The order in which the rings are placed on the fingers does not matter in this context because each ring is independently placed on any of the 5 fingers.
- The formula (51)5(41)4(31)3(21)2(11)1\binom{5}{1} \cdot 5 \cdot \binom{4}{1} \cdot 4 \cdot \binom{3}{1} \cdot 3 \cdot \binom{2}{1} \cdot 2 \cdot \binom{1}{1} \cdot 1 is not applicable here because it assumes a different context where the order of selection and placement is considered differently.

The final answer is 55\boxed{5^5}.

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Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic and difficulty added by this site.